A small particle of mass m moves in such a way that its potential energy U= 1 2mω ^2 ^2 where ω is constant and r is the distance of the particle…
JEE Main 2023 — Physics Mechanics
2023mcqhard
A small particle of mass m moves in such a way that its potential energy U=21mω2r2 where ω is constant and r is the distance of the particle from origin. Assuming Bohr’s quantization of momentum and circular orbit, the radius of nth orbit will be proportional to
Official previous-year question
Held on 6 Apr 2023 · Verified 6 Jul 2026.
Options
A
n
B
n1
C
n2
D
n
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Solution
The data given is
U=21mω2r2
From Bohr's quantization,
mvr=2πnh⇒v2=(2πrmnh)2...(i)
In an orbit the value of the kinetic energy is half of the potential energy,
K=4mω2r2
Substituting the value of equation (i) in the kinetic energy,
K=21m(4π2m2r2n2h2)=4mω2r2⇒2π2m2ω2n2h2=r4⇒r∝n
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