It is given that v=40ms−1.
The components of the velocity will be vy=vsin30∘=240ms−1=20ms−1vx=vcos30∘=2403ms−1=203ms−1
The time taken to reach maximum height is T=gusin30∘=10ms−220ms−1=2s
Hence, at T=2s,asvy=0ms−1thereforevnet=vx=203ms−1.