The given data is
v=60ms−1u=10ms−1a=2ms−2
Using the equation v=u+at, we get
60=10+2t⇒t=2(60−10)⇒t=25s
A particle starts with an initial velocity of 10.0ms−1 along x-direction and accelerates uniformly at the rate of 2.0ms−2. The time taken by the particle to reach the velocity of 60.0ms−1 is _____.
Held on 6 Apr 2023 · Verified 6 Jul 2026.
25s
3s
6s
30s
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