
Given here, v2v1=23
Using conservation of momentum during disintegration, we have
m1v1=m2v2⇒m2m1=32
Since, m=34πR3ρ
We have m∝R3(∵nuclear mass density,ρ=constant)
m2m1=(R2R1)3
⇒R2R1=(32)31
So, x=2.
JEE Main 2023 — Physics Mechanics
A nucleus disintegrates into two smaller parts, which have their velocities in the ratio 3:2. The ratio of their nuclear sizes will be (3x)31. The value of ‘x’ is:
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