Displacement in nth second is given by Sn=u+2a(2n−1)
Here, displacement is 8th second is
S8=0+21×10×(2×8−1)
⇒S8=75m
Loss of potential energy is
ΔU=mgS8=0.4×10×75
⇒ΔU=300J.
A 0.4kg mass takes 8s to reach ground when dropped from a certain height P above surface of earth. The loss of potential energy in the last second of fall is ______ J. [Take g=10ms−2]
Held on 29 Jan 2023 · Verified 6 Jul 2026.
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