Required lift force, F=P2A−P1A=5.4×105×g
⇒P2−P1=5005.4×106=5.4×2×103
=10.8×103
Now applying Bernoulli's Theorem we get
P2+0+21ρV22=P1+0+21ρV12
⇒P2−P1=21ρ(V12−V22)=21ρ(V1−V2)(V1+V2)[Since for small change,V1=V2=V=1080kmh−1=300ms−1]
⇒10.8×103=21×1.2(V1−V2)×2×300
⇒10.8×10=3.6(V1−V2)
⇒V1−V2=30
Therefore, fractional increase will be(VV1−V2)×100=30030×100=10