
Given here, u=5ms−1,h=10m
Using vy2=uy2+2gh in vertical direction, we have the velocity of stone in vertical direction as vy=2gh=200ms−1 (since, uy=0).
The final velocity along the horizontal direction is the same as the initial horizontal velocity as there is no acceleration along the x-axis.
The speed with which the stone hits the ground is
vnet=vx2+vy2=25+200=15ms−1