Let the mass of the bullet be m and mass of the block be M. It is given that V=400ms−1. By conservation of momentum,
mV=(m+M)v
⇒0.1×400=(0.1+3.9)v
⇒v=10ms−1
The force acting on the block
f=μm′g⇒a=μg
Using v′2−v2=−2aS
⇒ 02−102=2(−μg)(S)
⇒μ=2×10×20100=0.25