
Applying Newton's second law along the direction perpendicular to inlined plane:
N−mgcos30∘=0 (As θ=30∘)
(since the acceleration of block in the direction perpendicular to the inclined plane is 0)
∴N=mgcos30∘ .....(1)
Let μ be the coefficient of kinetic friction between the block and the inclined plane. Applying Newton's second law along inclined plane:
mgsin30∘−μN=ma=m4g ....(2)
(since the acceleration along the inclined plane, a=4g)
∴mgsin30∘−μmgcos30∘=m4g (from equation 1 and 2)
⇒2mg−23μmg=m4g
⇒μ=231