Forces acting on block is shown below

From the second equation of motion,
s=21at2⇒50=21a×102⇒a=1ms−2
Applying Newton's second law in vertical direction,
R−mg=0⇒R=mg
(where R is the magnitude of normal reaction on the block due to the surface)
If μ is the coefficient of kinetic friction between the block and the surface, applying Newton's second law in horizontal direction,
30−μR=ma⇒30−μmg=ma⇒30−50μ=5⇒μ=21=0.5