
Using s=ut+21at2
Initially, u=0, so time taken to reach from A to B is t=g2s=9.82×4.9=1s
Now, using v2=u2+2as, we have
v=2gh=2×9.8×4.9=9.8ms−1
∵t2=(4−1)s=3s
∴d=t2×v=3×9.8=29.4m
JEE Main 2022 — Physics Mechanics
When a ball is dropped into a lake from a height 4.9m above the water level, it hits the water with a velocity v and then sinks to the bottom with the constant velocity v. It reaches the bottom of the lake 4.0s after it is dropped. The approximate depth of the lake is
Held on 27 Jun 2022 · Verified 6 Jul 2026.
39.2m
19.6m
73.5m
29.4m
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