Given that m2m1=34,r2r1=43
Now the total energy of a satellite TE=21mvo2+(r−GMm)
Since the orbital speed of a satellite vo=rGM
⇒TE=−2rGMm∝rm
⇒TE2TE1=m2m1⋅r1r2=34×34=916
JEE Main 2022 — Physics Mechanics
Two satellites A and B having masses in the ratio 4:3 are revolving in circular orbits of radii 3r and 4r respectively around the earth. The ratio of total mechanical energy of A to B is
Held on 27 Jul 2022 · Verified 6 Jul 2026.
9:16
16:9
1:1
4:3
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