After collision, the balls change their directions of motion without changing the magnitudes of their velocity.

Change in momentum of any one ball
∣Δp∣=2×0.05×10
⇒∣Δp∣=1kgms−1
The force exerted on the ball is ∣Fav∣=Δt∣Δp∣=0.0051
Fav=200N
Two billiard balls of mass 0.05kg each moving in opposite directions with 10ms−1 collide and rebound with the same speed. If the time duration of contact is t=0.005s, then what is the force exerted on the ball due to each other?
Held on 25 Jul 2022 · Verified 6 Jul 2026.
100N
200N
300N
400N
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