Three identical spheres each of mass M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 3m each.…
JEE Main 2022 — Physics Mechanics
2022integerhard
Three identical spheres each of mass M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 3m each. Taking point of intersection of mutually perpendicular sides as origin, the magnitude of position vector of centre of mass of the system will be xm. The value of x is
Official previous-year question
Held on 25 Jul 2022 · Verified 6 Jul 2026.
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Solution
The diagram represents the locations of the masses as mentioned in the question.
For point 1, r1=0i^+0j^ for point 2, r2=3i^+0j^ and for point 3, r3=0i^+3j^.
The formula for centre of mass is
rcom=m1+m2+m3m1r1+m2r2+m3r3
⇒rcom=3MM(0i^+0j^)+M(3i^)+M(3j^)
⇒rcom=i^+j^
∣rcom∣=12+12=2=x
⇒x=2
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