Vernier constant is the least count of the vernier V.C=0.1mm=0.01cm
zero error =−0.05cm
∴correction=0.05cm
M.S.R.=1.7cm
V.S.R.=5V.C.=5×0.01=0.05cm
The diameter of the sphere will be,
diameter=MSR+VSR+correction
1.7+0.05+0.05=1.8cm
=180×10−2cm
JEE Main 2022 — Physics Mechanics
The Vernier constant of Vernier callipers is 0.1mm and it has zero error of (−0.05cm). While measuring diameter of a sphere, the main scale reading is 1.7cm and coinciding vernier division is 5 . The corrected diameter will be _____×10−2cm.
Held on 29 Jun 2022 · Verified 6 Jul 2026.
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