∵2(I2+I3)+I4=xI1
Now
For solid sphere about its diameter I1=52MR2,
For solid cylinder about its axis I2=21MR2,
For circular disc about its diameter I3=41MR2
And for circular ring about its diameter I4=21MR2
⇒2(2MR2+4MR2)+2MR2=x×52MR2
⇒2(43)+21=x×52
⇒2=x×52
⇒x=5