We know that, Young's modulus is Y=AΔLFL, where, F is force or load acting on wire, A is cross-section area, L is length and ΔL is extension in length.
Now, from given graph, the slope of the line is =LWΔL=WLΔL=YA1
⇒Y=(slope)A1
Thus, Young's modulus of the steel wires is Y=2×10−6(0.25×10−5)1
⇒Y=2×1011Nm−2.
Therefore, x=2.
