Net force while going upward will be mg+R=50+10=60N
⇒aup=560=12ms−2
Similarly, Net force while going downward will be mg−R=40N
⇒ad=540=8ms−2
Since
h=21at2⇒adtd2auptup2=1⇒tdtup=128=32
An object of mass 5kg is thrown vertically upwards from the ground. The air resistance produces a constant retarding force of 10N throughout the motion. The ratio of time of ascent to the time of descent will be equal to : [Use g=10ms−2].
Held on 24 Jun 2022 · Verified 6 Jul 2026.
1:1
2:3
3:2
2:3
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