

Let a be the acceleration of block and α be the angular acceleration of disc.
Now, for unwrapping without slipping, Rα=a.
Forces acting on block are shown in FDB.
Using Newton's second law
mg−T=ma...(1)
Torque about centre of disc is τ=Ia
TR=2MR2α=24R2α=⇒T=2Rα...(2)
Putting the value of tension in equation (1), we get
mg−2Rα=ma⇒mg−2RRa=ma⇒mg−2a=ma⇒ma+2a=mg⇒a=m+2mg=2+22×10=5ms−2
Now, α=0.15=50rads−2
Tension in the cord is T=2×0.1×50=10N.