The average value of the readings is xavg=41.19+1.20+1.22+1.23=1.21
Now, absolute error in measurement Δxavg=40.02+0.01+0.01+0.02=40.06=0.015
Percentage error in measurement is =1.210.015×100=121150
So, the value of x=150.
JEE Main 2022 — Physics Mechanics
A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22mm,1.23mm,1.19mm and 1.20mm. The percentage error is 121x. The value of x is _____ .
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