Pressure inside a bubble is given by, P0+r4T.
Pressure inside the bubble of smaller radius will be,
P2−P1=[(P0+64T)+34T]
Pressure inside the bubble with radius r, P0+r4T
Now,
⇒P0+64T+34T=P0+r4T
⇒r1=61+31
⇒r=2cm
A spherical soap bubble of radius 3cm is formed inside another spherical soap bubble of radius 6cm. If the internal pressure of the smaller bubble of radius 3cm in the above system is equal to the internal pressure of the another single soap bubble of radius rcm. The value of r is _____
Held on 27 Jul 2022 · Verified 6 Jul 2026.
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