
Using equation of motion, v2=u2+2as
v2=0+2(−g)(−h)
⇒v2=2gh
Initial velocity of ball is v=2gh=20h.
If after entering the water this velocity does not change, then this value should be equal to the terminal velocity.
Then, 2gh=92ηr2(ρ−σ)g, here, ρ is density of ball, σ is density of water and η is viscosity.
⇒20h=921×10−5(0.1×10−3)2(104−103)10⇒20h=921×10−510−8(10−1)103×10
⇒20h=400
∴h=20m