
Component of velocity in horizontal direction,
vx=20cosα=v2cosβ
Component of velocity in vertical direction,
vy=20sinα−g×10=v2sinβ
⇒tanβ=20cosα20sinα−100
⇒tanβ=tanα−cosα5
⇒tanβ=tanα−5secα
A projectile is launched at an angle α with the horizontal with a velocity 20ms−1. After 10s, its inclination with horizontal is β. The value of tanβ will be : (g=10ms−2).
Held on 27 Jun 2022 · Verified 6 Jul 2026.
tanα+5secα
tanα−5secα
2tanα−5secα
2tanα+5secα
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