
The distance travelled by the person d will be equal to the arch length.
⇒d=Rθ
⇒60=R(43π)
⇒R=3π60×4=π80m
Now the magnitude of displacement can be found using subtraction of vectors. Therefore,
∣s∣=R22+R12−2R1R2cosθ⇒∣s∣=R2+R2−2R2cos135∘
⇒2R2−2R2(−0.7)
⇒3.4R2=3.4(π80)2
⇒R=47m
A person moved from A to B on a circular path as shown in figure. If the distance travelled by him is 60m, then the magnitude of displacement would…
JEE Main 2022 — Physics Mechanics
A person moved from A to B on a circular path as shown in figure. If the distance travelled by him is 60m, then the magnitude of displacement would be : (Given cos135∘=−0.7)
Held on 25 Jul 2022 · Verified 1 Jul 2026.
Options
- A
42m
- B
47m
- C
19m
- D
40m
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