For first drop.
h=21g(2n)2
For 2nd drop
h′=21g(n)2
h′h=14
h′=4h=49.8
so height of 2nd drop
H=h−h′=9.8−49.8=43×9.8=7.35m
JEE Main 2021 — Physics Mechanics
Water drops are falling from a nozzle of a shower onto the floor from a height of 9.8m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.
Held on 27 Aug 2021 · Verified 6 Jul 2026.
2.94m
4.18m
2.45m
7.35m
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