In 4thsec, 1st drop will travel
⇒21×(9.8)×(4)2=78.4m
∴2nd drop would have travelled
⇒78.4−34.3=44.1m
Time for 2nd drop
21(9.8)t2=44.1
t=3sec
∴ Each drop have time gap of 1sec.
∴1 drop per second.
JEE Main 2021 — Physics Mechanics
Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4th second after its fall to the next droplet is 34.3m. At what rate the droplets are coming from the tap ? (Take g=9.8ms−2)
Held on 25 Jul 2021 · Verified 6 Jul 2026.
3 drops/2 seconds
2 drops/second
1 drop/second
1 drop/7 seconds
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