For Aπr2E=ya2mm...(1)
For B π⋅16r2E=yb4mm...(2)
∴(1)/(2)
16=4a2b
ba=321
∴ =32
Two separate wires A and B are stretched by 2mm and 4mm respectively, when they are subjected to a force of 2N. Assume that both the wires are made up of same material and the radius of wire B is 4 times that of the radius of wire A. The length of the wires A and B are in the ratio of a:b. Then ba can be expressed as x1, where x is _____.
Held on 18 Mar 2021 · Verified 6 Jul 2026.
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