⇒T=2πGMr3
⇒TA=2πGM(6400+600)×103
⇒TB=2π×109GM83
⇒TB−TA=GM2π109[88−77]
=314×4.107
=1289.64
=1.289×103s
JEE Main 2021 — Physics Mechanics
Two satellites A and B of masses 200kg and 400kg are revolving round the earth at height of 600km and 1600km respectively. If TA and TB are the time periods of A and B respectively then the value of TB−TA :
[ Given : radius of earth =6400km, mass of earth =6×1024kg ]
Held on 25 Feb 2021 · Verified 6 Jul 2026.
4.24×103s
3.33×102s
1.33×103s
4.24×102s
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