Given, W1=W2 and, we know that work done is a scalar quantity it means, F1Scos45∘=F2Scos60∘⇒F2F1=21=x1⇒x=2.
Two persons A and B perform same amount of work in moving a body through a certain distance d with application of forces acting at angles 45∘ and 60∘ with the direction of displacement respectively. The ratio of force applied by person A to the force applied by person B is x1. The value of x is _________.
Held on 27 Aug 2021 · Verified 6 Jul 2026.
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Net gravitational force at the center of a square is found to be $F_{1}$ when four particles having mass $M, 2 M, 3 M$ and $4 M$ are placed at the four corners of the square as shown in figure and it is $F_{2}$ when the positions of $3 M$ and $4 M$ are interchanged. The ratio $\frac{F_{1}}{F_{2}}$ is $\frac{\alpha}{\sqrt{5}}$. The value of $\alpha$ is $\_\_\_\_$. 
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The surface tension of a soap solution is $3.5 \times 10^{-2}$ N/m. The work required to increase the radius of a soap bubble from $1$ cm to $2$ cm is $\alpha \times 10^{-6}$ J. The value of $\alpha$ is _____. ($\pi = 22/7$)
Work through every JEE Main Mechanics PYQ, year by year.