T=2πgℓ⇒g=T24π2ℓ
gΔg=ℓΔℓ+T2ΔT
ΔT=numberofoscillations(n)leastcountoftime(ΔT0)
gΔg=ℓΔℓ+nT2ΔT0
As Δℓ and ΔT0 are same for all observations so
gΔg is minimum for highest value of ℓ,n and T
⇒ Minimum percentage error in g is for student number 1.