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The velocity of a particle is v=(v_0+gt+Ft^2)ms^-1. Its position is x=0 at t=0; then its displacement after time (t=1s) is :

JEE Main 2021 — Physics Mechanics

2021mcqmedium

The velocity of a particle is v=(v0+gt+Ft2)ms−1v=({v}_{0}+gt+F{t}^{2})m{s}^{-1}v=(v0​+gt+Ft2)ms−1. Its position is x=0x=0x=0 at t=0;t=0;t=0; then its displacement after time (t=1s)(t=1s)(t=1s) is :

Official previous-year question

Held on 17 Mar 2021 · Verified 6 Jul 2026.

Options

  1. A

    v0+g+F{v}_{0}+g+Fv0​+g+F

  2. B

    v0+g2+F3{v}_{0}+\frac{g}{2}+\frac{F}{3}v0​+2g​+3F​

  3. C

    v0+g2+F{v}_{0}+\frac{g}{2}+Fv0​+2g​+F

  4. D

    v0+2g+3F{v}_{0}+2g+3Fv0​+2g+3F

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