g=T24π2l
gΔg=lΔl+2TΔT=100.1+2(0.52001)
gΔg=1001+501
gΔg×100=3
The time period of a simple pendulum is given by T=2π √ g. The measured value of the length of the pendulum is 10 cm known to a 1 mm accuracy. The…
JEE Main 2021 — Physics Mechanics
The time period of a simple pendulum is given by T=2πgl. The measured value of the length of the pendulum is 10cm known to a 1mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1s resolution. The percentage accuracy in the determination of g using this pendulum is x. The value of x to the nearest integer is:-
Held on 18 Mar 2021 · Verified 1 Jul 2026.
Options
- A
2
- B
3
- C
5
- D
4
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