Given
Translation K.E. of N2=K.E of electron
23kT=eV
23×1.38×10−23T=1.6×10−19×0.1⇒T=773K
T=773−273=500∘C
The average translational kinetic energy of N2 gas molecules at _________C\circ becomes equal to the K.E. of an electron accelerated from rest through a potential difference of 0.1volt.
(Given kB=1.38×10−23JK−1) (Fill the nearest integer).
Held on 1 Sept 2021 · Verified 6 Jul 2026.
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