Ring I1=2MR2 about diameter
Disc I2=2MR2
Solid cylinder I3=2MR2
Solid sphere I4=52MR2
I1=I2=I3>I4
JEE Main 2021 — Physics Mechanics
Moment of inertia (M.I.) of four bodies, having same mass and radius, are reported as;
I1=M.I. of thin circular ring about its diameter,
I2=M.I. of circular disc about an axis perpendicular to disc and going through the centre,
I3=M.I. of solid cylinder about its axis and
I4=M.I. of solid sphere about its diameter.
Then:
Held on 24 Feb 2021 · Verified 6 Jul 2026.
I1+I2=I3+25I4.
I1+I3<I2+I4
I1=I2=I3>I4
I1=I2=I3<I4
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