We know,
∵OA+OB+OC+OD+OE+OF+OG+OH=0
By triangle law of vector addition, we can write
AB=AO+OB;AC=AO+OC
AD=AO+OD;AE=AO+OE
AF=AO+OF;AG=AO+OG
AH=AO+OH
Now
AB+AC+AD+AE+AF+AG+AH
=(7AO)+OB+OC+OD+OE+OF+OG+OH
=(7AO)+0−OA
=(7AO)+AO
=8AO=8(2i^+3j^−4k^)
=16i^+24j^−32k^