We know,
∵OA+OB+OC+OD+OE+OF+OG+OH=0
By triangle law of vector addition, we can write
AB=AO+OB;AC=AO+OC
AD=AO+OD;AE=AO+OE
AF=AO+OF;AG=AO+OG
AH=AO+OH
Now
AB+AC+AD+AE+AF+AG+AH
=(7AO)+OB+OC+OD+OE+OF+OG+OH
=(7AO)+0−OA
=(7AO)+AO
=8AO=8(2i^+3j^−4k^)
=16i^+24j^−32k^
In an octagon ABCDEFGH of equal side, what is the sum of AB+ AC+ AD+ AE+ AF+ AG+ AH, if, AO=2 i+3 j-4 k
JEE Main 2021 — Physics Mechanics
In an octagon ABCDEFGH of equal side, what is the sum of AB+AC+AD+AE+AF+AG+AH, if, AO=2i^+3j^−4k^
Held on 25 Feb 2021 · Verified 1 Jul 2026.
Options
- A
16i^+24j^−32k^
- B
16i^−24j^+32k^
- C
16i^+24j^+32k^
- D
−16i^−24j^+32k^
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