
21kx2=21mv2
Kx2=mv2
v=xmk=0.050.1100=0.05×1010
v=0.510
From h=21gt2
t=g2h=102×2=102
∴d=vt=0.510×102=1m
In a spring gun having spring constant 100Nm−1 a small ball B of mass 100g is put in its barrel (as shown in figure) by compressing the spring through 0.05m. There should be a box placed at a distance d on the ground so that the ball falls in it. If the ball leaves the gun horizontally at a height of 2m above the ground. The value of d is m.
(g=10ms−2)

Held on 20 Jul 2021 · Verified 6 Jul 2026.
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