m=24kg
A=0.4m2
a=1cm2
H=40cm
Using Bernoulli's equation,
⇒(P0+Amg)+ρgH+21Pv12
=P0+0+21ρv2...(1)
⇒ Neglecting v1
⇒v=2gH+Aρ2mg
⇒v=8+1.2
⇒v=3.033ms−1
⇒v≃3ms−1
Consider a water tank as shown in the figure. It's cross-sectional area is 0.4m^2. The tank has an opening B near the bottom whose cross-section area…
JEE Main 2021 — Physics Mechanics
2021integerhard
Consider a water tank as shown in the figure. It's cross-sectional area is 0.4m2. The tank has an opening B near the bottom whose cross-section area is 1cm2. A load of 24kg is applied on the water at the top when the height of the water level is 40cm above the bottom, the velocity of water coming out the opening B is vms−1. The value of v, to the nearest integer, is ___ .[Take the value of g to be 10ms−2]
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Held on 18 Mar 2021 · Verified 6 Jul 2026.
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