
Component along AC
=100cos35∘N
=100×0.819N
=81.9N
≈82N
JEE Main 2021 — Physics Mechanics
Consider a frame that is made up of two thin massless rods AB and AC as shown in the figure. A vertical force P of magnitude 100N is applied at point A of the frame.

Suppose the force is P resolved parallel to the arms AB and AC of the frame. The magnitude of the resolved component along the arm AC is xN. The value of x, to the nearest integer, is ________.
[Given : sin(35∘)=0.573,cos(35∘)=0.819,sin(110∘)=0.939,cos(110∘)=−0.342]
Held on 16 Mar 2021 · Verified 6 Jul 2026.
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