R0=1ΩR1=
ℓ0=1mℓ1=1.25m
A0=A
As volume of wire remains constant so
A0ℓ0=A1ℓ1⇒A1=ℓ1ℓ0A0
Now, Resistance (R)=Aρℓ
R1R0=ρℓ1/A1ℓ0/A0
R11=A0ℓ0(ℓ1×ℓ1ℓ0A0)R1=ℓ02ℓ12=1.5625Ω
So change in resistance
=R0R1−R0×100
=11.5625−1×100
=56.25