
F=Y.A⋅lΔl⇒Δl=Y.A.F⋅l⇒Δl=Y.πr2F.l⇒Δl∝r2l
Δl1Δl2=(l1l2)(r2r1)2=(2)(21)2⇒Δl1Δl2=21⇒Δl2=2Δl1
=20.04=0.02m⇒Δl2=2cm.
A uniform metallic wire is elongated by 0.04m when subjected to a linear force F. The elongation, if its length and diameter is doubled and subjected to the same force will be _________ cm.
Held on 24 Feb 2021 · Verified 6 Jul 2026.
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