F=4i^−3j^
r1=5i^+53j^ and r2=−5i^+53j^
Torque about ′O′
τO=r1×F=(−15−203)k^
Torque about ′Q′
τQ=r2×F=(15−203)k^
JEE Main 2021 — Physics Mechanics
A triangular plate is shown. A force F=4i^−3j^ is applied at point P. The torque at point P with respect to point O and Q are:

Held on 17 Mar 2021 · Verified 6 Jul 2026.
−15−203,15−203
15+203,15−203
15−203,15+203
−15+203,15+203
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