Using conservation of angular momentum
⇒(Mr2)ω=(Mr2+2mr2)ω′
⇒ω′=M+2mMω.
A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω. Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become:
Held on 18 Mar 2021 · Verified 6 Jul 2026.
ωM+mM
ωMM+2m
ωM+2mM
ωM+2mM−2m
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