Let's take solid cylinder is in equilibrium
T+f=mgsin60
TR−fR=0
Solving we get
T=freq=2mgsinθ
But limiting friction < required friction
μmgcos60∘<2mgsin60∘
∴ Hence cylinder will not remain in equilibrium
Hence f= kinetic
=μkN
=μkmgcos60∘
=5mg
A solid cylinder of mass m is wrapped with an inextensible light string and, is placed on a rough inclined plane as shown in the figure. The…
JEE Main 2021 — Physics Mechanics
2021mcqmedium
A solid cylinder of mass m is wrapped with an inextensible light string and, is placed on a rough inclined plane as shown in the figure. The frictional force acting between the cylinder and the inclined plane is:
[The coefficient of static friction, μs, is 0.4 ]
Official previous-year question
Held on 18 Mar 2021 · Verified 6 Jul 2026.
Options
- A
27mg
- B
5mg
- C
5mg
- D
0
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