Draw vt curve

tanθ1=a1=t1vmax
&\mathrm{tan}{\theta }_{2}={a}_{2}=\frac{{v}_{\mathrm{max}}}{{t}_{2}}
÷ above
t2t1=a1a2
JEE Main 2021 — Physics Mechanics
A scooter accelerates from rest for time t1 at constant rate a1 and then retards at constant rate a2 for time t2 and comes to rest. The correct value of t2t1 will be :
Held on 26 Feb 2021 · Verified 6 Jul 2026.
a1a2
a2a1
a1a1+a2
a2a1+a2
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