θ=45∘
H=2gu2sin2θ=2×10(25)2×(21)=8125m
and time t=2T
=gusinθ=1025(21)=10225=225s
JEE Main 2021 — Physics Mechanics
A player kicks a football with an initial speed of 25ms−1 at an angle of 45∘ from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion? (Take g=10ms−2)
Held on 27 Aug 2021 · Verified 6 Jul 2026.
hmax=15.625m,T=1.77s
hmax=3.54m,T=0.125s
hmax=10m,T=2.5s
hmax=15.625m,T=3.54s
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