yΔy=m2Δm+r4Δr+gxΔg+23lΔl
18=2(1)+4(0.5)+xp+23(4)
8=xp
By checking from options.
x=316,p=±23
JEE Main 2021 — Physics Mechanics
A physical quantity y is represented by the formula y=m2r−4gxl−23 If the percentage errors found in y,m,r,l and g are 18,1,0.5,4 and p respectively, then find the value of x and p.
Held on 27 Jul 2021 · Verified 6 Jul 2026.
5 and ±2
4 and ±3
316 and ±23
8 and ±2
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