t=0,u=0
a=MFo−MT2Fo(t−T)2=dtdv
∫0vdv=∫t=02T(MFo−MT2Fo(t−T)2)dt
V=[MFot]o2T−MT2Fo[3t3−t2T+T2t]02T
V=3M4FoT
JEE Main 2021 — Physics Mechanics
A particle of mass M originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation F=F0[1−(Tt−T)2] where F0 and T are constants. The force acts only for the time interval 2T. The velocity v of the particle after time 2T is:
Held on 27 Jul 2021 · Verified 6 Jul 2026.
M2F0T
2MF0T
3M4F0T
3MF0T
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