
v0=αt1 and 0=v0−βt2⇒v0=βt2
t1+t2=t
v0(α1+β1)=t
⇒v0=α+βαβt
Distance = area of v−t graph
=21×t×v0=21×t×α+βαβt=2(α+β)αβt2
A car accelerates from rest at a constant rate α for some time after which it decelerates at a constant rate β to come to rest. If the total time elapsed is t seconds, the total distance travelled is:
Held on 17 Mar 2021 · Verified 6 Jul 2026.
(α+β)4αβt2
(α+β)2αβt2
2(α+β)αβt2
4(α+β)αβt2
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