Let's say the compression in the spring by:y. So, by work-energy theorem we have
⇒21mv2=21ky2⇒y=km⋅v⇒y=1004×10⇒y=2m
⇒ Final length of spring,=8−2=6m.
JEE Main 2021 — Physics Mechanics
A ball of mass 4kg, moving with a velocity of 10ms−1, collides with a spring of length 8m and force constant 100Nm−1. The length of the compressed spring is xm. The value of x, to the nearest integer, is ___ .
Held on 18 Mar 2021 · Verified 6 Jul 2026.
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